在ASP.NET中实现Model-View-Controller模式（三）

模型及控制器部分：

这个解决方案的第二个部分是被隐藏的后台代码：

using System;

using System.Data;

using System.Data.SqlClient;

public class Solution : System.Web.UI.Page

{

   protected System.Web.UI.WebControls.Button submit;

   protected System.Web.UI.WebControls.DataGrid MyDataGrid;

   protected System.Web.UI.WebControls.DropDownList recordingSelect;

   private void Page_Load(object sender, System.EventArgs e)

   {

      if(!IsPostBack)

      {

         String selectCmd = "select * from Recording";

         SqlConnection myConnection =

            new SqlConnection(

               "server=(local);database=recordings;Trusted_Connection=yes");

         SqlDataAdapter myCommand = new SqlDataAdapter(selectCmd, myConnection);

         DataSet ds = new DataSet();

         myCommand.Fill(ds, "Recording");

         recordingSelect.DataSource = ds;

         recordingSelect.DataTextField = "title";

         recordingSelect.DataValueField = "id";

         recordingSelect.DataBind();

      }

   }

   void SubmitBtn_Click(Object sender, EventArgs e)

   {  

      String selectCmd =

         String.Format(

         "select * from Track where recordingId = {0} order by id",

         (string)recordingSelect.SelectedItem.Value);

      SqlConnection myConnection =

         new SqlConnection(

            "server=(local);database=recordings;Trusted_Connection=yes");

      SqlDataAdapter myCommand = new SqlDataAdapter(selectCmd, myConnection);

      DataSet ds = new DataSet();

      myCommand.Fill(ds, "Track");

      MyDataGrid.DataSource = ds;

      MyDataGrid.DataBind();

   }

   #region Web Form Designer generated code

   override protected void OnInit(EventArgs e)

   {

      //

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