p; 22 42 58 70 56 38 16
23 43 59 71 79 69 55 37 15
24 44 60 72 80 84 78 68 54 36 14
1 25 45 61 73 81 85 83 77 67 53 35 13
2 26 46 62 74 82 76 66 52 34 12
3 27 47 63 75 65 51 33 11
4 28 48 64 50 32 10
5 29 49 31 9
6 30 8
7
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想来是的, 这样你看如何?
代码:--------------------------------------------------------------------------------
1 select replace(max(sys_connect_by_path(rank, '''','''')), '''','''') str
2 from (select i, j,
3 to_char(rank() over(order by tag), ''''9999'''') as rank
4 from (select i,
5 j,
6 -- 逆时针螺旋特征码 counter-clockwise
7 case least(j - 1, &&1 - i, &1 - j, i - 1)
8 when j - 1 then
9 (j - 1) || ''''1'''' || i
10 when &1 - i then
11 (&1 - i) || ''''2'''' || j
12 when &1 - j then
13 (&1 - j) || ''''3'''' || (&1 - i)
14 when i - 1 then
15 (i - 1) || ''''4'''' || (&1 - j)
16 end as tag
17 from (select level as i from dual connect by level <= &1) a,
18 (select level as j from dual connect by level <= &1) b
19 )
20 )
21 start with j = 1
22 connect by j - 1 = prior j and i = prior i
23 group by i
24* order by i
SQL> /
输入 1 的值: 5
原值 7: case least(j - 1, &&1 - i, &1 - j, i - 1)
新值 7: case least(j - 1, 5 - i, 5 - j, i - 1)
原值 10: when &1 - i then
新值 10: when 5 - i then
原值 11: (&1 - i) || ''''2'''' || j
新值 11: (5 - i) || ''''2'''' || j
原值 12: when &1 - j then
新值 12: when 5 - j then
原值 13: (&1 - j) || ''''3'''' || (&1 - i)
新值 13: (5 - j) || ''''3'''' || (5 - i)
原值 15: (i - 1) || 上一页 [1] [2] [3] [4] [5] [6] 下一页 |
