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操作Oracle数据库实现上传图片到Blob类型的字段出现的问题         ★★★★

操作Oracle数据库实现上传图片到Blob类型的字段出现的问题

作者:闵涛 文章来源:闵涛的学习笔记 点击数:716 更新时间:2009/4/22 22:06:50

通过使用OleDb操作Oracle数据库,成功实现图片上传到Blob类型的字段,但有时会发生ORA-01036错误的问题,经查询是错误提示为illegal variable name/number,不知道有谁能详细解释illegal variable name/number的意思

Oracle Data Provider for .NET
Hi
I am using ODP.NET (Oracle Data Provider for .NET) in my asp.net application.
I have a table in my oracle database called "equipmentgroup". When the page loads for the first time i retrieve all the records from the table to a dataset and save it to viewstate. Later on any addition or modification is done in the dataset only in disconnected mode. Finally,when user clicks update i call this function "update" which should do a batch update but instead it gives the following error :

"ORA-01036: illegal variable name/number "


        private void update()
        {
            OracleParameter workParam;

            OracleConnection cnn = new OracleConnection("Data Source=NEELESHR;User Id=tmse; Password=tmse;");
            string sql = "INSERT INTO EquipmentGroup (Code, Description, LifeTime, PriamryLife, Grading, Inflator, ExtensionRate, MaintenanceFee) VALUES (:Code, :Description, :LifeTime, :PriamryLife, :Grading, :Inflator, :ExtensionRate, :MaintenanceFee)";
            OracleCommand cmd = new OracleCommand(sql,cnn);
            cmd.CommandType = CommandType.Text;            

            OracleDataAdapter da = new OracleDataAdapter();
            da.InsertCommand = cmd;
            
            workParam = da.InsertCommand.Parameters.Add("Code",OracleType.Char,10,"Code");
            workParam.SourceVersion = DataRowVersion.Current;

            workParam = da.InsertCommand.Parameters.Add("Description",OracleType.VarChar,50,"Description");
            workParam.SourceVersion = DataRowVersion.Current;

            workParam = da.InsertCommand.Parameters.Add("LifeTime",OracleType.Number);
            workParam.SourceColumn = "LifeTime";
            workParam.SourceVersion = DataRowVersion.Current;

            workParam = da.InsertCommand.Parameters.Add("PriamryLife",OracleType.Number);
            workParam.SourceColumn = "PriamryLife";
            workParam.SourceVersion = DataRowVersion.Current;

            workParam = da.InsertCommand.Parameters.Add("Grading",OracleType.Char,10,"Grading");
            workParam.SourceVersion = DataRowVersion.Current;

            workParam = da.InsertCommand.Parameters.Add("Inflator",OracleType.Number);
            workParam.SourceColumn = "Inflator";
            workParam.SourceVersion = DataRowVersion.Current;

            workParam = da.InsertCommand.Parameters.Add("ExtensionRate",OracleType.Number);
            workParam.SourceColumn = "ExtensionRate";
            workParam.SourceVersion = DataRowVersion.Current;

            workParam = da.InsertCommand.Parameters.Add("MaintenanceFee",OracleType.Number);
            workParam.SourceColumn = "MaintenanceFee";
            workParam.SourceVersion = DataRowVersion.Current;
            

            try
            {
                da.Update(ds,"EquipmentGroup");
            }
            catch(Exception e)
            {
                Message.Text = e.Message;
            }

        }

Hi,

I think that you should add parameters with ":" included, like:
workParam =
da.InsertCommand.Parameters.Add(":Code",OracleType.Char,10,"Code");

OleDb Data Provider for .NET

string sql = "INSERT INTO EquipmentGroup (Code, Description, LifeTime, PriamryLife, Grading, Inflator, ExtensionRate, MaintenanceFee) VALUES (?, ?, ?, ?, ?, ?, ?, ?, )";

Hi,

I think that you should add parameters with ":" included, like:
workParam =
da.InsertCommand.Parameters.Add(":Code",OracleType.Char,10,"Code");


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